Imagine
that in the vertical of a given point in Ecuador, a geostationary
satellite rises. As is known, this satellite will be found at a height
of 36,000km., Which is the geostationary altitude or place where the
orbital velocity is synchronous with the Earth's rotation (when the
satellite rotates in the same direction).
We
ask for the help of Superman, which offers us unconditionally very
solicitous. We moved to Ecuador, just at the point on the earth's
surface whose vertical geostationary satellite is mentioned above.
Now
we ask Superman to take a small stone and without relying on earth,
throw it with calculated strength so hard and so way than ascend
vertically right up to the height at which the satellite orbit is, one
iota more nor less.
Armed
with diving, we rise following the stone (we impose our mass, as
observers, does not interfere with the experiment). We see the stone, as
the satellite approaching, will slowing its ascent until he stops for a
moment, just when it reaches its height. A moment later, he begins its
descent will be completed, as is known, at just over 1.4 hours.
And
this is where we find the paradox. If we consider the moment in which
the stone has stopped his ascent, the initial conditions of both systems
(a geostationary satellite and stone), are identical, not its previous
"history", yet one still in orbit while the other starts his fall.
We
build a second experiment. With the help of Superman, which collects a
lot of Kripto-steel, a material of extreme hardness and resistance yet
shows no mass or gravitational field, we build a huge tower of Pisa of
36,000km. height, the upper terrace is right next to the geostationary
satellite so if stretch out our hands from it can come to touch it.
Emulating
Galileo and again imposing our mass does not interfere with the
experiment, we take a stone from the surface of the Earth and ascend the
tower to reach the terrace. We extend a hand holding the stone
collected on Earth, right next to the geostationary satellite.
We
can be thus arbitrarily long time, imposing the masses of satellite and
stone not interfere with each other or with the experiment until we
decide to release the stone. What will happen? Will the stone be
suspended just off the orbiting satellite? Will start to fall until it
reaches the surface in about 1.4 hours?
The
answer is that the stone will fall but then the paradox arises: How is
it possible that the previous "history" condition the result of the
experiment?
We
can only resolve this paradox if "accept" that the geostationary
satellite is "loaded" of dark energy (I prefer to call her:
antigravity).
But, what is it that mysterious dark energy or antigravity ?.
It is neither more nor less than the kinetic energy accumulated by the satellite:
½ m v².
But,
as we know from Einstein (E = mc²), that energy (½ mv²), although in a
very small value should weigh. That is, it should contribute to the
satellite "fall" instead of keeping it suspended.
Should we rethink the "vision" of Einstein? Is energy "weighs"? That is, the energy creates gravitational field (E = mc²)?
That
is precisely the position that I posit: E ≠ mc². Energy not only
creates an attractive gravitational field, but interacting with matter,
curved spacetime in reverse as it does this.
Einstein's
equation is valid only for systems at rest and matter-energy
transformations (read the atomic bomb), but overall, I postulate that
energy does not weigh, but rather the contrary, the energy is
strongly repelled by gravity and is the mysterious "dark energy" that
scientists so seek.
Way
similar to how matter curves space-time "creating" gravity energy the
curve in the opposite direction creating anti-gravity or dark energy.
Of
the energy equation of a satellite link we can derive the following if
we consider the example of the geostationary satellite, the kinetic
energy neutralizes exactly the "weight" or centripetal force that should
bring down the satellite.
For official physics is the centrifugal force that opposes the weight. I posit that the kinetic energy is dark energy, which when passing through the gravitational field, as similar to what happens in electromagnetism , a force that opposes the weight and the value appears as follows:
In
this equation, mg is the resultant force that opposes the weight, mi g
is the local weight at rest, v is the transverse velocity (relative to
the gravitational field) and vo is the local orbital velocity.
We can simplify the antigravity equation: m = mi (1 - v² / vo²).
Thus we obtain the apparent mass from the initial function of transverse velocity and the local orbital.
That mass can be negative, if the transverse velocity is greater than the local orbital speed, and when multiplied by the value of the local gravitational field strength: g, we get the dark energy or antigravity generated.
We can simplify the antigravity equation: m = mi (1 - v² / vo²).
Thus we obtain the apparent mass from the initial function of transverse velocity and the local orbital.
That mass can be negative, if the transverse velocity is greater than the local orbital speed, and when multiplied by the value of the local gravitational field strength: g, we get the dark energy or antigravity generated.
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